Six on dice

What is the probability that when throwing two dice will fall at least one six?

Result

p =  0.306

Solution:

p=(6+6−1)/(6⋅ 6)=1136≐0.3056≐0.306p=(6+6-1)/(6 \cdot \ 6)=\dfrac{ 11 }{ 36 } \doteq 0.3056 \doteq 0.306

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