Dices throws

What is the probability that the two throws of the dice:

a) Six falls even once
b) Six will fall at least once

Correct answer:

p₁ =  0.6944
p₂ =  0.3056

Step-by-step explanation:

$$\begin{gathered} q_1={\displaystyle \frac{1}{6}}\doteq 0.1667 \\ {q}_2=1-q_1=1-0.1667={\displaystyle \frac{5}{6}}\doteq 0.8333 \\ {p}_1=q_2^2=0.8333^2={\displaystyle \frac{25}{36}}=0.6944 \end{gathered}$$

$p_2=q_1+q_1-q_1\cdot q_1=0.3056$

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