# Dices throws

What is the probability that the two throws of the dice:

a) Six falls even once
b) Six will fall at least once

Result

p1 =  0.694
p2 =  0.306

#### Solution:

$q_{ 1 } = \dfrac{ 1 }{ 6 } \doteq 0.1667 \ \\ q_{ 2 } = 1 - q_{ 1 } = 1 - 0.1667 = \dfrac{ 5 }{ 6 } \doteq 0.8333 \ \\ p_{ 1 } = q_{ 2 }^2 = 0.8333^2 = \dfrac{ 25 }{ 36 } \doteq 0.6944 = 0.694$
$p_{2}=q_{ 1 } + q_{ 1 } -q_{ 1 } \cdot \ q_{ 1 } = 0.306$

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