Throw

We throw 2 times with 2 dices. What is the probability that the first roll will fall more than sum of 9 and the second throw have sum 3 or does not have the sum 4?

Result

p =  55.556 %

Solution:

p=100 (124)/12 (122)/12=55.556%p=100 \cdot \ (12-4)/12 \cdot \ (12-2)/12=55.556 \%



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