Line slope calculator 3x+5y=21
Straight line given by points A[2; 3] and B[7; 0]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+4.2
Canonical form of the line equation: 3x+5y-21 = 0
Parametric form of the line equation:
x = 5t+2
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 7
Y intercept: y0 = q = 4.2
Distance line from the origin: d0 = 3.6015
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [4.5; 1.5]
Perpendicular Bisector equation: 5x-3y-18 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (7; 0) ; |OB| = 7
Scalar product OA .OB = 14
Angle ∠ AOB = 56°18'36″ = 0.9828 rad