Line slope calculator 4x-3y=18
Straight line given by points A[6; 2] and B[9; 6]
Calculation:
Slope: m = 1.3333Slope-intercept form of line: y = 1.3333x-6
Canonical form of the line equation: 4x-3y-18 = 0
Parametric form of the line equation:
x = 3t+6
y = 4t+2 ; t ∈ R
Slope angle of line: φ = 53°7'48″ = 0.9273 rad
X intercept: x0 = 4.5
Y intercept: y0 = q = -6
Distance line from the origin: d0 = 3.6
The length of the segment AB: |AB| = 5
Vector: AB = (3; 4)
Normal vector: n = (4; -3)
Midpoint of the segment AB: M = [7.5; 4]
Perpendicular Bisector equation: 3x+4y-38.5 = 0
Vector OA = (6; 2) ; |OA| = 6.3246
Vector OB = (9; 6) ; |OB| = 10.8167
Scalar product OA .OB = 66
Angle ∠ AOB = 15°15'18″ = 0.2663 rad