Line slope calculator 9x+4y=40


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[4; 1]

Calculation:

Slope-intercept form of line: y = -2.25x+10

Canonical form of the line equation: 9x+4y-40 = 0

Parametric form of the line equation:
x = 4t
y = -9t+10      ; t ∈ R

Slope: m = -2.25

Slope angle of line: φ = -66°2'15″ = -1.1526 rad

X intercept: x0 = 4.4444

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 4.0614

The length of the segment AB: |AB| = 9.8489

Vector: AB = (4; -9)

Normal vector: n = (9; 4)

Midpoint of the segment AB: M = [2; 5.5]

Perpendicular Bisector equation: 4x-9y+41.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 10
Angle ∠ AOB = 75°57'50″ = 1.3258 rad