Line slope calculator 2x+4y=40
Straight line given by points A[0; 10] and B[4; 8]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+10
Canonical form of the line equation: 2x+4y-40 = 0
Parametric form of the line equation:
x = 4t
y = -2t+10 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 20
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 8.9443
The length of the segment AB: |AB| = 4.4721
Vector: AB = (4; -2)
Normal vector: n = (2; 4)
Midpoint of the segment AB: M = [2; 9]
Perpendicular Bisector equation: 4x-2y+10 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (4; 8) ; |OB| = 8.9443
Scalar product OA .OB = 80
Angle ∠ AOB = 26°33'54″ = 0.4636 rad