Line slope calculator 9x+8y=80


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -1.125x+10

Canonical form of the line equation: 9x+8y-80 = 0

Parametric form of the line equation:
x = 8t
y = -9t+10      ; t ∈ R

Slope: m = -1.125

Slope angle of line: φ = -48°21'59″ = -0.8442 rad

X intercept: x0 = 8.8889

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 6.6436

The length of the segment AB: |AB| = 12.0416

Vector: AB = (8; -9)

Normal vector: n = (9; 8)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 8x-9y+17.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 10
Angle ∠ AOB = 82°52'30″ = 1.4464 rad