Line slope calculator 9x+8y=80
Straight line given by points A[0; 10] and B[8; 1]
Calculation:
Slope: m = -1.125Slope-intercept form of line: y = -1.125x+10
Canonical form of the line equation: 9x+8y-80 = 0
Parametric form of the line equation:
x = 8t
y = -9t+10 ; t ∈ R
Slope angle of line: φ = -48°21'59″ = -0.8442 rad
X intercept: x0 = 8.8889
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 6.6436
The length of the segment AB: |AB| = 12.0416
Vector: AB = (8; -9)
Normal vector: n = (9; 8)
Midpoint of the segment AB: M = [4; 5.5]
Perpendicular Bisector equation: 8x-9y+17.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 10
Angle ∠ AOB = 82°52'30″ = 1.4464 rad