Line slope calculator 4x+5y=30
Straight line given by points A[0; 6] and B[5; 2]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+6
Canonical form of the line equation: 4x+5y-30 = 0
Parametric form of the line equation:
x = 5t
y = -4t+6 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 7.5
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 4.6852
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [2.5; 4]
Perpendicular Bisector equation: 5x-4y+3.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (5; 2) ; |OB| = 5.3852
Scalar product OA .OB = 12
Angle ∠ AOB = 68°11'55″ = 1.1903 rad