Line slope calculator x-4y=-10


Enter coordinates of two different points:

Straight line given by points A[2; 3] and B[6; 4]

Calculation:

Slope-intercept form of line: y = 0.25x+2.5

Canonical form of the line equation: x-4y+10 = 0

Parametric form of the line equation:
x = 4t+2
y = t+3      ; t ∈ R

Slope: m = 0.25

Slope angle of line: φ = 14°2'10″ = 0.245 rad

X intercept: x0 = -10

Y intercept: y0 = q = 2.5

Distance line from the origin: d0 = 2.4254

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; 1)

Normal vector: n = (1; -4)

Midpoint of the segment AB: M = [4; 3.5]

Perpendicular Bisector equation: 4x+y-19.5 = 0


Vector OA = (2; 3) ;   |OA| = 3.6056
Vector OB = (6; 4) ;   |OB| = 7.2111
Scalar product OA .OB = 24
Angle ∠ AOB = 22°37'11″ = 0.3948 rad