Line slope calculator 7x-6y=15
Straight line given by points A[3; 1] and B[9; 8]
Calculation:
Slope: m = 1.1667Slope-intercept form of line: y = 1.1667x-2.5
Canonical form of the line equation: 7x-6y-15 = 0
Parametric form of the line equation:
x = 6t+3
y = 7t+1 ; t ∈ R
Slope angle of line: φ = 49°23'55″ = 0.8622 rad
X intercept: x0 = 2.1429
Y intercept: y0 = q = -2.5
Distance line from the origin: d0 = 1.627
The length of the segment AB: |AB| = 9.2195
Vector: AB = (6; 7)
Normal vector: n = (7; -6)
Midpoint of the segment AB: M = [6; 4.5]
Perpendicular Bisector equation: 6x+7y-67.5 = 0
Vector OA = (3; 1) ; |OA| = 3.1623
Vector OB = (9; 8) ; |OB| = 12.0416
Scalar product OA .OB = 35
Angle ∠ AOB = 23°11'55″ = 0.4049 rad