Line slope calculator 4x-3y=16


Enter coordinates of two different points:

Straight line given by points A[4; 0] and B[7; 4]

Calculation:

Slope-intercept form of line: y = 1.3333x-5.3333

Canonical form of the line equation: 4x-3y-16 = 0

Parametric form of the line equation:
x = 3t+4
y = 4t      ; t ∈ R

Slope: m = 1.3333

Slope angle of line: φ = 53°7'48″ = 0.9273 rad

X intercept: x0 = 4

Y intercept: y0 = q = -5.3333

Distance line from the origin: d0 = 3.2

The length of the segment AB: |AB| = 5

Vector: AB = (3; 4)

Normal vector: n = (4; -3)

Midpoint of the segment AB: M = [5.5; 2]

Perpendicular Bisector equation: 3x+4y-24.5 = 0


Vector OA = (4; 0) ;   |OA| = 4
Vector OB = (7; 4) ;   |OB| = 8.0623
Scalar product OA .OB = 28
Angle ∠ AOB = 29°44'42″ = 0.5191 rad