Line slope calculator 4x-3y=16
Straight line given by points A[4; 0] and B[7; 4]
Calculation:
Slope: m = 1.3333Slope-intercept form of line: y = 1.3333x-5.3333
Canonical form of the line equation: 4x-3y-16 = 0
Parametric form of the line equation:
x = 3t+4
y = 4t ; t ∈ R
Slope angle of line: φ = 53°7'48″ = 0.9273 rad
X intercept: x0 = 4
Y intercept: y0 = q = -5.3333
Distance line from the origin: d0 = 3.2
The length of the segment AB: |AB| = 5
Vector: AB = (3; 4)
Normal vector: n = (4; -3)
Midpoint of the segment AB: M = [5.5; 2]
Perpendicular Bisector equation: 3x+4y-24.5 = 0
Vector OA = (4; 0) ; |OA| = 4
Vector OB = (7; 4) ; |OB| = 8.0623
Scalar product OA .OB = 28
Angle ∠ AOB = 29°44'42″ = 0.5191 rad