Line slope calculator 4x+3y=35


Enter coordinates of two different points:

Straight line given by points A[5; 5] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -1.3333x+11.6667

Canonical form of the line equation: 4x+3y-35 = 0

Parametric form of the line equation:
x = 3t+5
y = -4t+5      ; t ∈ R

Slope: m = -1.3333

Slope angle of line: φ = -53°7'48″ = -0.9273 rad

X intercept: x0 = 8.75

Y intercept: y0 = q = 11.6667

Distance line from the origin: d0 = 7

The length of the segment AB: |AB| = 5

Vector: AB = (3; -4)

Normal vector: n = (4; 3)

Midpoint of the segment AB: M = [6.5; 3]

Perpendicular Bisector equation: 3x-4y-7.5 = 0


Vector OA = (5; 5) ;   |OA| = 7.0711
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 45
Angle ∠ AOB = 37°52'30″ = 0.661 rad