Line slope calculator 3x+2y=40


Enter coordinates of two different points:

Straight line given by points A[8; 8] and B[10; 5]

Calculation:

Slope-intercept form of line: y = -1.5x+20

Canonical form of the line equation: 3x+2y-40 = 0

Parametric form of the line equation:
x = 2t+8
y = -3t+8      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 13.3333

Y intercept: y0 = q = 20

Distance line from the origin: d0 = 11.094

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; -3)

Normal vector: n = (3; 2)

Midpoint of the segment AB: M = [9; 6.5]

Perpendicular Bisector equation: 2x-3y+1.5 = 0


Vector OA = (8; 8) ;   |OA| = 11.3137
Vector OB = (10; 5) ;   |OB| = 11.1803
Scalar product OA .OB = 120
Angle ∠ AOB = 18°26'6″ = 0.3218 rad