Temperature change 3

At 2 p. M. The temperature was 76 degrees Fahrenheit. At 8 p. M. The temperature was 58 degrees Fahrenheit. What was the change in temperature?

Result

c =  -18 °F

Solution:

t1=76 ∘F t2=58 ∘F  c=t2−t1=58−76=−18=−18∘Ft_{1}=76 \ ^\circ \text{F} \ \\ t_{2}=58 \ ^\circ \text{F} \ \\ \ \\ c=t_{2}-t_{1}=58-76=-18=-18 ^\circ \text{F}

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