# Nuts

How many we must have at least nuts if we can equally divide it to 10 children, 12 children or 15 children and any nut left?

Result

n =  60

#### Solution:

$10=2 \cdot 5 \ \\ 12=2^2 \cdot 3 \ \\ 15=3 \cdot 5 \ \\ LCM(10, 12, 15)=2^2 \cdot 3 \cdot 5=60 \ \\ \ \\ n=LCM(10,12,15)=60$

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