# Self-oscillation period

The water in the vessel carried by the boy has a self-oscillation period of 0.8 s. What is the size of the boy's movement speed when the length of the boy's step is 60 cm? Give the result in m/s.

Result

v =  0.75 m/s

#### Solution:

$T=0.8 \ \text{s} \ \\ s=60 \ cm=60 / 100 \ m=0.6 \ m \ \\ \ \\ λ=v T \ \\ s=v \cdot \ T \ \\ \ \\ v=s/T=0.6/0.8=\dfrac{ 3 }{ 4 }=0.75 \ \text{m/s}$

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