# Surface area 2

Calculate how many % reduce the surface area of the cube is we reduced length of each edge by 10%.

Correct result:

p =  19 %

#### Solution:

$p = 100 \cdot \dfrac{S_1 - S_2}{S_1} = 100 \cdot \dfrac{ 6a^2 - 6(0.9a)^2}{6a^2} \ \\ p = 100 \cdot \dfrac{ 1 - 0.9^2}{1} = 19 \%$

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