Sequence members

Determine the first twelve members of the sequence if a13 = 95, d = 17

Final Answer:

a12 =  78
a11 =  61
a10 =  44
a9 =  27
a8 =  10
a7 =  -7
a6 =  -24
a5 =  -41
a4 =  -58
a3 =  -75
a2 =  -92
a1 =  -109

Step-by-step explanation:

a12​=95−17=78
a11​=78−17=61
a10​=61−17=44
a9​=44−17=27
a8​=27−17=10
a7​=10−17=−7
a6​=−7−17=−24
a5​=−24−17=−41
a4​=−41−17=−58
a3​=−58−17=−75
a2​=−75−17=−92
a1​=−92−17=−109

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