# Parametric equation

Find the parametric equation of a line with y-intercept (0,-4) and a slope of -2.

Result

p = (Correct answer is: x=t; y=-4-2t)

#### Solution:

$y = kx+q \ \\ k = -2 \ \\ y = -2x+q \ \\ -4 = -2 \cdot \ 0+q \ \\ q = -4 \ \\ y = -2x-4 \ \\ p: x = t \ \\ y = -4-2t; t\in R \ \\ p=x = t; y = -4-2t$

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