Mixer work

What was the useful work output of a mixer with an efficiency of 30% if it consumed 4.5 kWh of energy?

Final Answer:

x =  15 kWh

Step-by-step explanation:

r=30%=10030=103=0.3  x r=4.5 kWh  x=4.5/r=4.5/0.3=15 kWh



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