Camping trip

A group of friends on a camping trip has 3 2/5 lb of trail mix. They divide it up evenly among themselves. Each person gets 1/5 lb of the trail mix.

How many friends are on the camping trip?

Correct result:

n =  17

Solution:

$$\begin{gathered} m=3{\displaystyle \frac{2}{5}}={\displaystyle \frac{3\cdot 5+2}{5}}={\displaystyle \frac{17}{5}}=3.4\text{ lb } \\ {m}_1={\displaystyle \frac{1}{5}}=0.2\text{ lb } \\ n=m\mathrm{/}{m}_1=3.4\mathrm{/}0.2=17 \end{gathered}$$

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