# The ball

The ball was discounted by 10 percent and then again by 30 percent. How many percent of the original price is now?

Result

p =  63 %

#### Solution:

$q=(1-10/100) \cdot \ (1-30/100)=\dfrac{ 63 }{ 100 }=0.63 \ \\ \ \\ p=100 \cdot \ q=100 \cdot \ 0.63=63=63 \%$

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