The ball

The ball was discounted by 10 percent and then again by 30 percent. How many percent of the original price is now?

Correct answer:

p =  63 %

Step-by-step explanation:

$$\begin{gathered} q_1=1-10\mathrm{/}100={\displaystyle \frac{9}{10}}=0.9 \\ {q}_2=1-30\mathrm{/}100={\displaystyle \frac{7}{10}}=0.7 \\ q=q_1\cdot q_2=0.9\cdot 0.7={\displaystyle \frac{63}{100}}=0.63 \\ p=100\cdot q=100\cdot 0.63=63\mathrm{\%} \end{gathered}$$

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