Nineteenth member

Find the nineteenth member of the arithmetic sequence:

a1=33
d=5
find a19

Result

a19 =  123

Solution:

a1=33 d=5 n=19  a19=a1+(n−1)⋅ d=33+(19−1)⋅ 5=123a_{1}=33 \ \\ d=5 \ \\ n=19 \ \\ \ \\ a_{19}=a_{1} + (n-1) \cdot \ d=33 + (19-1) \cdot \ 5=123

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