Imagine that a unit of air at a temperature of 25°C rises a mountain range 3,000 meters high on the windward side and which descends to 1,200 meters on the leeward side, assuming that the air will remain dry. What will its temperature be when it crosses the top of the range, and what will it be when it descends to the base on the lee side? (temperature decreases 6 degrees Celcius for every 1000 meters)

Correct answer:

t1 =  7 °C
t2 =  17.8 °C

Step-by-step explanation:

t1=256 10003000=7°C
t2=256 10001200=589°C=17.8°C

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