Delta t

The temperature decreased 14°F between 10 PM and 4 AM. The temperature at 4 AM was 67°F. What was the temperature at 10 PM?

Correct answer:

t1 =  81 °F

Step-by-step explanation:

Δ=14 °F t2=67 °F  t2 = t1+Δ  t1=t2Δ=67(14)=81°F



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