Temperature 79404

The aluminum coil line has a resistance of 4.6 Ohm at an elevated temperature of 64°C. At what base temperature will the resistance be 2 ohms?

Final Answer:

t₂ =  -77.3043 °C

Step-by-step explanation:

$$\begin{gathered} t_1=64\text{°C} \\ {R}_1=4.6\Omega \\ \alpha =0.004 \\ {R}_2=2\Omega \\ {R}_2=R_1-R_1\cdot \alpha \cdot \Delta \\ \Delta =\frac{R_1-R_2}{\alpha \cdot R_1}=\frac{4.6-2}{0.004\cdot 4.6}=\frac{3250}{23}\doteq 141.3043\text{°C} \\ {t}_2=t_1-\Delta =64-141.3043=-77.3043\text{°C} \end{gathered}$$

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