Vimla

Vimla purchased 10 m of curtain material; she stitched 3 curtains of length 2 1/4 m, 1 1/2 m, and 2 1/2 m. How much material is left unstitched?

Correct answer:

x =  3 ³⁄₄ = 15/4 m

Step-by-step explanation:

$$\begin{gathered} a=10\text{m} \\ b=2\frac{1}{4}=2+\frac{1}{4}=\frac{2\cdot 4+1}{4}=\frac{8+1}{4}=\frac{9}{4}=2.25\text{m} \\ c=1\frac{1}{2}=1+\frac{1}{2}=\frac{1\cdot 2+1}{2}=\frac{2+1}{2}=\frac{3}{2}=1.5\text{m} \\ d=2\frac{1}{2}=2+\frac{1}{2}=\frac{2\cdot 2+1}{2}=\frac{4+1}{2}=\frac{5}{2}=2.5\text{m} \\ s=b+c+d=\frac{9}{4}+\frac{3}{2}+\frac{5}{2}=\frac{9}{4}+\frac{6}{4}+\frac{10}{4}=\frac{9+6+10}{4}=\frac{25}{4}=6.25\text{m} \\ x=a-s=10-\frac{25}{4}=\frac{10\cdot 4}{4}-\frac{25}{4}=\frac{40}{4}-\frac{25}{4}=\frac{40-25}{4}=\frac{15}{4}=\frac{15}{4}\text{m}=3\frac{3}{4}\text{m}=3.75\text{m} \end{gathered}$$

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