Three-holiday 8149

During the holidays, 159 pupils were accommodated in three holiday cottages marked with the letters A, B, and C. There were 8 more pupils accommodated in cottage B than in cottage A and 14 more pupils in cottage C than in cottage B. How many pupils were accommodated in individual cottages?

Correct answer:

A =  43
B =  51
C =  65

Step-by-step explanation:


A+B+C=159
B = 8 + A
C = 14+B

A+B+C = 159
A-B = -8
B-C = -14

Row 2 - Row 1 → Row 2
A+B+C = 159
-2B-C = -167
B-C = -14

Row 3 - 1/-2 · Row 2 → Row 3
A+B+C = 159
-2B-C = -167
-1.5C = -97.5


C = -97.5/-1.5 = 65
B = -167+C/-2 = -167+65/-2 = 51
A = 159-B-C = 159-51-65 = 43

A = 43
B = 51
C = 65

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