Resistance 82714

A load of 23.5 ohm is connected to an ideal voltage source of 30V, and a current of 1.2A passes through the circuit. Determine the magnitude of the source's internal resistance and the short-circuit current.

Correct answer:

R2 =  1.5 Ω
I2 =  20 A

Step-by-step explanation:

U=30 V R1=23.5 Ω I=1.2 A  I=U/R U=(R1+R2) I  R2=U/IR1=30/1.223.5=1.5 Ω
I2=R2U=1.530=20 A



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