Elevator efficiency

To what height will an elevator motor with a power of 25 kW and an efficiency of 48.6% transport a cabin weighing 445 kg with seven people (the average weight of one person is 64 kg) if it takes 54 seconds?

Correct answer:

h =  73.4714 m

Step-by-step explanation:

P=25 kW W=25 1000  W=25000 W ξ=48.6%=10048.6=0.486 m1=445 kg m2=7 64=448 kg t=54 s g=10 m/s2  Q=P ξ=25000 0.486=12150 W E=Q t=12150 54=656100 J  m=m1+m2=445+448=893 kg  E = m g h  h=m gE=893 10656100=73.4714 m



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