Procedure 9191

Behind the tractor, which travels at 12 km/h, they sent a car 3.5 hours later to catch up with him in 45 minutes. What speed does he have to go?

Please also explain the procedure.

Correct answer:

v =  68 km/h

Step-by-step explanation:

t1=3.5 h t2=45 min h=45:60  h=0.75 h  s=12 (t1+t2)=12 (3.5+0.75)=51 km  s = v t  v=s/t2=51/0.75=68 km/h

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