Cyclist

The cyclist rode two-fifths of the way the first day. On the second day drove 5 km less while traveling three-eighths of the route. How many kilometers does he have to finish the target?

Final Answer:

x =  45 km

Step-by-step explanation:

$$\begin{gathered} a=2/5t \\ b=a-5 \\ b=3/8t \\ a=2/5t \\ a-5=3/8t \\ (2/5t)-5=3/8t \\ (2/5\cdot t)-5=3/8\cdot t \\ t=200 \\ a=\frac{2}{5}\cdot t=\frac{2}{5}\cdot 200=\frac{2\cdot 200}{5}=\frac{400}{5}=80\text{km} \\ b=a-5=80-5=75\text{km} \\ x=t-a-b=200-80-75=45\text{km} \end{gathered}$$

Try another example