Cyclist Three Day Route

The cyclist drives a 240 km long route in 3 days. On the first day, go half of the entire route. The second day passed two-fifths of the rest of the way. What percentage of the cyclist completed the whole way on the third day?

Final Answer:

p =  30 %

Step-by-step explanation:

$$\begin{gathered} s=240\text{km} \\ a=s/2=240/2=120\text{km} \\ b=\frac{2}{5}\cdot (s-a)=\frac{2}{5}\cdot (240-120)=48\text{km} \\ c=s-a-b=240-120-48=72\text{km} \\ p=100\cdot \frac{c}{s}=100\cdot \frac{72}{240}=\frac{100\cdot 72}{240}=\frac{7200}{240}=30\% \end{gathered}$$

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