3 phase load

Two wattmeters are connected to measuring power in a 3 phase balanced load. Determine the total power and power factor if the two wattmeters read 1000 watts each (1) both positive and (2) second reading is negative.

Correct answer:

P₁ =  2000 W
f₁ =  1
P₂ =  0 W
f₂ =  0

Step-by-step explanation:

$$\begin{gathered} P_{11}=1000\text{ W } \\ {P}_{21}=1000\text{ W } \\ {P}_1=P_{11}+P_{21}=1000+1000=2000\text{ W} \end{gathered}$$

$$\begin{gathered} P_{12}=1000\text{ W } \\ {P}_{22}=-1000\text{ W } \\ {P}_2=P_{12}+P_{22}=1000+(-1000)=0\text{ W} \end{gathered}$$

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