# The perimeter of the rectangle

The length, l, of a rectangle is 4 inches greater than its width, w. The perimeter of the rectangle is at least 30 inches. What inequality shows the range of possible widths of the rectangle?

Result

i = (Correct answer is: ?)

#### Solution:

$l=4+w \ \\ p=2l + 2w \ \\ p>=30 \ \\ \ \\ \ \\ p=2l + 2w \ \\ p=2(4+w) + 2w \ \\ p=8+4w \ \\ \ \\ 8+4w >=30 \ \\ 4w >=22 \ \\ w >=11/2 \ \\ \ \\ i=?$

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