Mary

Mary is 12 years old, which is 40% of the age of her mother. How many percent of her mother's age will Mary have after the next 12 years?

Result

p =  57.143 %

Solution:

 12=0.40⋅ m  0.4m=12  m=30  p=100⋅ 12+12m+12=100⋅ 12+1230+12=4007≐57.1429=57.143% \ \\ 12 = 0.40 \cdot \ m \ \\ \ \\ 0.4m = 12 \ \\ \ \\ m = 30 \ \\ \ \\ p = 100 \cdot \ \dfrac{ 12+12 }{ m+12 } = 100 \cdot \ \dfrac{ 12+12 }{ 30+12 } = \dfrac{ 400 }{ 7 } \doteq 57.1429 = 57.143 \%

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