Temperature calculus

Calculate percentage of temperature increase if changed from 18°C to 33°C?

Result

p =  5.152 %

Solution:

t1=18 ∘C t2=33 ∘C T1=273.15+t1=273.15+18=582320=291.15 K T2=273.15+t2=273.15+33=612320=306.15 K  p=100⋅ T2−T1T1=100⋅ 306.15−291.15291.15≐5.152≐5.152%t_{1}=18 \ ^\circ \text{C} \ \\ t_{2}=33 \ ^\circ \text{C} \ \\ T_{1}=273.15 + t_{1}=273.15 + 18=\dfrac{ 5823 }{ 20 }=291.15 \ \text{K} \ \\ T_{2}=273.15 + t_{2}=273.15 + 33=\dfrac{ 6123 }{ 20 }=306.15 \ \text{K} \ \\ \ \\ p=100 \cdot \ \dfrac{ T_{2}-T_{1} }{ T_{1} }=100 \cdot \ \dfrac{ 306.15-291.15 }{ 291.15 } \doteq 5.152 \doteq 5.152 \%

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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

Showing 2 comments:
#
Math student
this is unclear

#
Dr Math
I think that percent change of temperature is made in Kelvins (absolute temperature).

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