# Temperature calculus

Calculate percentage of temperature increase if changed from 18°C to 33°C?

Result

p =  5.152 %

#### Solution:

$t_{1}=18 \ ^\circ \text{C} \ \\ t_{2}=33 \ ^\circ \text{C} \ \\ T_{1}=273.15 + t_{1}=273.15 + 18=\dfrac{ 5823 }{ 20 }=291.15 \ \text{K} \ \\ T_{2}=273.15 + t_{2}=273.15 + 33=\dfrac{ 6123 }{ 20 }=306.15 \ \text{K} \ \\ \ \\ p=100 \cdot \ \dfrac{ T_{2}-T_{1} }{ T_{1} }=100 \cdot \ \dfrac{ 306.15-291.15 }{ 291.15 } \doteq 5.152 \doteq 5.152 \%$

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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

Math student
this is unclear

Dr Math
I think that percent change of temperature is made in Kelvins (absolute temperature).

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