3 years

The company has increased the number of employees. In year 2005 compared to 2004 13% more, in 2006 18% more against the previous year, in year 2007 20% more compared to 2006. How many % increase in the number of employees in 3 years?

Correct result:

p =  60 %

Solution:

$p=100\cdot ((1+13\mathrm{/}100)\cdot (1+18\mathrm{/}100)\cdot (1+20\mathrm{/}100)-1)={\displaystyle \frac{7501}{125}}\mathrm{\%}=60\mathrm{\%}$

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