3 years

The company has increased the number of employees. In year 2005 compared to 2004 13% more, in 2006 18% more against the previous year, in year 2007 20% more compared to 2006. How many % increase in the number of employees in 3 years?

Correct result:

p =  60 %

Solution:

p=100⋅ ((1+13/100)⋅ (1+18/100)⋅ (1+20/100)−1)=7501125=60%p=100 \cdot \ ((1+13/100) \cdot \ (1+18/100) \cdot \ (1+20/100)-1)=\dfrac{ 7501 }{ 125 }=60 \%

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