# Arm-leg

Calculate the length of the base of an isosceles triangle with a circumference 224 cm if the arm length is 68 cm.

Result

x =  88 cm

#### Solution:

$o = 224 \ cm \ \\ r = 68 \ cm \ \\ \ \\ o = x + 2r \ \\ \ \\ x = o - 2 \cdot \ r = 224 - 2 \cdot \ 68 = 88 = 88 \ \text{ cm }$

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