Crane overload

The truck crane has a load capacity of 4 tons. How many kilograms can we overload it if the maximum limit of 115 percent load capacity is allowed?

Final Answer:

x =  600 kg

Step-by-step explanation:

$$\begin{gathered} a=4\text{t}\to \text{kg}=4\cdot 1000\text{kg}=4000\text{kg} \\ r=115\%=\frac{115}{100}=\frac{23}{20}=1.15 \\ x=a\cdot (r-1)=4000\cdot (1.15-1)=600\text{kg} \end{gathered}$$

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