The temperature 6

The temperature was 47°F on Thursday and 60°F on Friday. How much did the temperature rise?

Result

d =  13 °F

Solution:

t1=47 ∘F t2=60 ∘F  d=t2−t1=60−47=13=13∘Ft_{1}=47 \ ^\circ \text{F} \ \\ t_{2}=60 \ ^\circ \text{F} \ \\ \ \\ d=t_{2}-t_{1}=60-47=13=13 ^\circ \text{F}

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