Cube 5

The surface of the cube is 15.36 dm2. How will change the surface area of this cube if the length of the edges is reduced by 2 cm?

Correct result:

S =  11.76 dm2
S1 - S2 =  3.6 dm2

Solution:

S=6a2=15.36 dm2 a=S/6=1.6 dm a2=a−0.2=1.4 dm S2=6a22=11.76 dm2S= 6a^2 = 15.36\ dm^2 \ \\ a = \sqrt{S/6} = 1.6 \ dm \ \\ a_2 = a-0.2 = 1.4 \ dm \ \\ S_2 = 6a_2^2 = 11.76 \ \text{dm}^2
S1−S2=15.36−11.76=185 dm2=3.6 dm2

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