AS - sequence

What are the first ten members of the sequence if a11=22, d=2.

Result

a10 =  20
a9 =  18
a8 =  16
a7 =  14
a6 =  12
a5 =  10
a4 =  8
a3 =  6
a2 =  4
a1 =  2

Solution:

a10=22−2=20a_{10}=22-2=20
a9=20−2=18a_9=20-2=18
a8=18−2=16a_8=18-2=16
a7=16−2=14a_7=16-2=14
a6=14−2=12a_6=14-2=12
a5=12−2=10a_5=12-2=10
a4=10−2=8a_4=10-2=8
a3=8−2=6a_3=8-2=6
a2=6−2=4a_2=6-2=4
a1=4−2=2a_1=4-2=2

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