# Sequence 2

Write the first 5 members of an arithmetic sequence a11=-14, d=-1

Correct result:

a1 =  -4
a2 =  -5
a3 =  -6
a4 =  -7
a5 =  -8

#### Solution:

${a}_{1}=-14-\left(11-1\right)\cdot \left(-1\right)=-4$
${a}_{2}={a}_{1}-1=-5$
${a}_{3}={a}_{2}-1=-6$
${a}_{4}={a}_{3}-1=-7$
${a}_{5}={a}_{4}-1=-8$

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