# Sequence 3

Write the first 5 members of an arithmetic sequence: a4=-35, a11=-105.

Result

a1 =  -5
a2 =  -15
a3 =  -25
a4 =  -35
a5 =  -45

#### Solution:

$-35 = a_1 + (4-1)d \ \\ -105 = a_1 + (11-1)d \ \\ \ \\ d = -10 \ \\ a_1 = -5 \ \\$
$a_2 = a_1 -10 = -15$
$a_3 = a_2 -10 = -25$
$a_4 = a_3 -10 = -35$
$a_5 = a_4 -10 = -45$

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