Sequence 3

Write the first 5 members of an arithmetic sequence: a4=-35, a11=-105.

Result

a1 =  -5
a2 =  -15
a3 =  -25
a4 =  -35
a5 =  -45

Solution:

−35=a1+(4−1)d −105=a1+(11−1)d  d=−10 a1=−5 -35 = a_1 + (4-1)d \ \\ -105 = a_1 + (11-1)d \ \\ \ \\ d = -10 \ \\ a_1 = -5 \ \\
a2=a1−10=−15a_2 = a_1 -10 = -15
a3=a2−10=−25a_3 = a_2 -10 = -25
a4=a3−10=−35a_4 = a_3 -10 = -35
a5=a4−10=−45a_5 = a_4 -10 = -45

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