# Sequence

Write the first 6 members of these sequence:

a1 = 5
a2 = 7
an+2 = an+1 +2 an

Result

a1 =  5
a2 =  7
a3 =  17
a4 =  31
a5 =  65
a6 =  127

#### Solution:

$a_1 = 5$
$a_2 = 7$
$a_3 = 7 +2 \cdot 5 = 17$
$a_4 = 17 +2 \cdot 7 = 31$
$a_5 = 31 +2 \cdot 17 = 65$
$a_6 = 65 +2 \cdot 31 = 127$

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