# Sequence

Write the first 6 members of these sequence:

a1 = 5
a2 = 7
an+2 = an+1 +2 an

Correct result:

a1 =  5
a2 =  7
a3 =  17
a4 =  31
a5 =  65
a6 =  127

#### Solution:

${a}_{1}=5$
${a}_{2}=7$
${a}_{3}=7+2\cdot 5=17$
${a}_{4}=17+2\cdot 7=31$
${a}_{5}=31+2\cdot 17=65$
${a}_{6}=65+2\cdot 31=127$

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