# Sequence - 5 members

Write first five members of the sequence
$a_n ={3n - (-1)^n} +2$

Result

a1 =  6
a2 =  7
a3 =  12
a4 =  13
a5 =  18

#### Solution:

$a_1=3 \cdot \ 1 - (-1)^{ 1 } +2 = 6$
$a_2=3 \cdot \ 2 - (-1)^{ 2 } +2 = 7$
$a_3=3 \cdot \ 3 - (-1)^{ 3 } +2 = 12$
$a_4=3 \cdot \ 4 - (-1)^{ 4 } +2 = 13$
$a_5=3 \cdot \ 5 - (-1)^{ 5 } +2 = 18$

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