Sequence - 5 members

Write first five members of the sequence
an=3n(1)n+2a_n ={3n - (-1)^n} +2


Result

a1 =  6
a2 =  7
a3 =  12
a4 =  13
a5 =  18

Solution:

a1=3 1(1)1+2=6a_1=3 \cdot \ 1 - (-1)^{ 1 } +2 = 6
a2=3 2(1)2+2=7a_2=3 \cdot \ 2 - (-1)^{ 2 } +2 = 7
a3=3 3(1)3+2=12a_3=3 \cdot \ 3 - (-1)^{ 3 } +2 = 12
a4=3 4(1)4+2=13a_4=3 \cdot \ 4 - (-1)^{ 4 } +2 = 13
a5=3 5(1)5+2=18a_5=3 \cdot \ 5 - (-1)^{ 5 } +2 = 18



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