Sequence - 5 members

Write first five members of the sequence

$a_n=3n-(-1{)}^n+2$

Correct result:

a₁ =  6
a₂ =  7
a₃ =  12
a₄ =  13
a₅ =  18

Solution:

$a_1=3\cdot 1-(-1{)}^1+2=6$

$a_2=3\cdot 2-(-1{)}^2+2=7$

$a_3=3\cdot 3-(-1{)}^3+2=12$

$a_4=3\cdot 4-(-1{)}^4+2=13$

$a_5=3\cdot 5-(-1{)}^5+2=18$

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