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The first machine can sow a field in 12 hours. The second, more powerful machine in 8 hours. How many hours was the field sown if workers deployed both machines, but the second machine started working 2 hours later than the first machine?

Correct answer:

t =  6 h

Step-by-step explanation:

t/12+(t2)/8=1  5t=30  t=530=6  t=6=6 h



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