The bulb

The bulb has a reading of 6V-0.05 A, what current flows through the bulb if we connect it to a cell with a voltage of 12V?

Correct result:

I₂ =  0.1 A

Solution:

$$\begin{gathered} U_1=6\text{ V } \\ {I}_1=0.05\text{ A } \\ {U}_2=12\text{ V } \\ R=U_1\mathrm{/}{I}_1=6\mathrm{/}0.05=120\mathrm{\Omega } \\ {I}_2=U_2\mathrm{/}R=12\mathrm{/}120={\displaystyle \frac{1}{10}}={\displaystyle \frac{1}{10}}\text{ A}=0.1\text{ A} \end{gathered}$$

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